<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[RSS Feed]]></title><description><![CDATA[RSS Feed]]></description><link>http://direct.ecency.com</link><image><url>http://direct.ecency.com/logo512.png</url><title>RSS Feed</title><link>http://direct.ecency.com</link></image><generator>RSS for Node</generator><lastBuildDate>Fri, 10 Apr 2026 11:56:33 GMT</lastBuildDate><atom:link href="http://direct.ecency.com/@konaw34/rss" rel="self" type="application/rss+xml"/><item><title><![CDATA[july cet2018]]></title><description><![CDATA[2017-2018 Basic Education High School, Kan Grade 10 , Mathematics, July C.E.T Time Allowed (45) minutes 1.Choose the correct or the most appropriate answer for each question. Write the letter of the correct]]></description><link>http://direct.ecency.com/behs/@konaw34/july-cet2018</link><guid isPermaLink="true">http://direct.ecency.com/behs/@konaw34/july-cet2018</guid><category><![CDATA[behs]]></category><dc:creator><![CDATA[konaw34]]></dc:creator><pubDate>Mon, 30 Jul 2018 03:26:21 GMT</pubDate></item><item><title><![CDATA[taungkhan cet]]></title><description><![CDATA[A. 1 B. 2 C. 2 D. 4 E. 5 The scientific notation 3.5 ×103 multiplied by 3 is A. 1.05 ×102 B.1.05×1010 C. 1.05×103 D.1.05×109 E. 1.05×104 The scientific notation 8.2×10-4 + 5.4×10-4=……… A.1.35×10-5 B. 1.36×10-4]]></description><link>http://direct.ecency.com/behs/@konaw34/taungkhan-cet</link><guid isPermaLink="true">http://direct.ecency.com/behs/@konaw34/taungkhan-cet</guid><category><![CDATA[behs]]></category><dc:creator><![CDATA[konaw34]]></dc:creator><pubDate>Sun, 29 Jul 2018 01:23:18 GMT</pubDate></item></channel></rss>