<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[RSS Feed]]></title><description><![CDATA[RSS Feed]]></description><link>http://direct.ecency.com</link><image><url>http://direct.ecency.com/logo512.png</url><title>RSS Feed</title><link>http://direct.ecency.com</link></image><generator>RSS for Node</generator><lastBuildDate>Sat, 11 Apr 2026 21:01:25 GMT</lastBuildDate><atom:link href="http://direct.ecency.com/@ngelay76/rss" rel="self" type="application/rss+xml"/><item><title><![CDATA[cetmessagge]]></title><description><![CDATA[Find the equation of the line through the point ( 2 , -1 ) and perpendicular to 4x -3y= 5. (5 marks ) Draw the graph of the relation R = {(-4,-3),(-3,-2),(-2,-1),(-1,0),(0,1),(1,2),(2,3),(3,4)}.]]></description><link>http://direct.ecency.com/behs/@ngelay76/cetmessagge</link><guid isPermaLink="true">http://direct.ecency.com/behs/@ngelay76/cetmessagge</guid><category><![CDATA[behs]]></category><dc:creator><![CDATA[ngelay76]]></dc:creator><pubDate>Mon, 30 Jul 2018 05:53:39 GMT</pubDate></item><item><title><![CDATA[geo kan]]></title><description><![CDATA[If a:b=3:8 and b:c=4:5, then a:c=………….. A. 5:11 B. 3:8 C. 3:11 D. 3:10 E. 5:8 If a:b=3:5 and b:c=3:5, then a:b:c=……… A. 2:3:5 B.3:5:7 C.6:10:15 D. 9:15:25 E.9:20:27 If a:b = 5:3 , then 3a+ 4b: 4a+3b is]]></description><link>http://direct.ecency.com/behs/@ngelay76/geo-kan</link><guid isPermaLink="true">http://direct.ecency.com/behs/@ngelay76/geo-kan</guid><category><![CDATA[behs]]></category><dc:creator><![CDATA[ngelay76]]></dc:creator><pubDate>Sun, 29 Jul 2018 01:23:36 GMT</pubDate></item></channel></rss>