N = 10 and M = 100 then B = 64, and C = nB = 640

No, as sum(n) = N; usually we use n to count things, here I've used it (not a great choice) as a value of one utxo. To have a chance to stake 64 times (within 16h) you would have to split N = 10 into 64 chunks of n=0.15625 each (equal ns for simplicity).

Hive account@tomasbrod commented on splitting coins, but his message is not clear to me.

Also,

• B – (time) maximum number of blocks that N coins can stake when M is a total number of staking coins

is not accurate enough

I meant

• B – (time) maximum number of blocks that N coins can stake within 16 h when M is a total number of staking coins
  (now updated in the main text, thanks)