Geometry of a Tetrahedron: Question 3: 3D Pythagorean Theorem

In this video I go over Question 3 of the Discovery Project: Geometry of a Tetrahedron. This question uses the results from Question 1, in which I calculated the areas of the 4 triangular faces. Using those results, I show that the area squared of the opposite triangular face is equal to the sum of the squares of the 3 areas adjacent to the opposite vertex. In other words, we have a three-dimensional version of the Pythagorean Theorem: D² = A² + B² + C²

This video was taken from my earlier video listed below:

Discovery Project: The Geometry of a Tetrahedron:
Video notes: @mes/discovery-project-geometry-of-a-tetrahedron
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