A week or two ago I had made a post link to post which included an encrypted message at the end. The encrypted message was "U Nvvl Eiuhm Jqzuaeye, Tqute Ubnpaqg vrr qjq Ypn". To decrypt this message you first have to gather all the unnecessary capital letters in the original post. The letters are L, P, E, S, G, E, C, A, M, W, W, E. Next you have to find the corresponding number of the alphabet to the letter, so L = 12, P = 16, E = 5, S = 19 , G = 7, E = 5, C = 3, A = 1, M = 13, W = 23, W = 23, E = 5. Now for the last step you shift the alphabet backwards the amount of the letter. I didn't just shift the letters though I added the previous shift into it. So U shifted back 12 will be I, the next letter N will be shifted 2 cause 12 + 16 = 28, which is more than 26 letters so we subtract 26 to get 2. If you continue to do this with the whole sequence you will get from the first letter to the last 12, 2, 7, 26, 7, 12, 15, 16, 3, 26, 23, 2. That will be the amount of shift for each letter. So the U shifts to 'I', N shifts to 'L', v shifts to 'o', if you continue this all the way through you will get: "I Love Steem Monsters, Earth Splinter for the Win!" Since no one got the correct answer I am giving the Medusa to
